Question
Using bisection method two times on the equation
We get the end points
a.
.
ob.
.
c.
.
d. None.
We get the end points
a.
ob.
c.
d. None.
Ask by Schneider Joseph. in Egypt
Mar 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The correct interval after two bisection method iterations is
.
Solution
To solve the equation
using the bisection method, we need to find the interval where the function
changes sign.
Given that the end points are
and
, we can use the bisection method to find the root of the equation.
Let’s denote the function as
.
-
Check the sign of
and : -
-
Determine the sign of
and : - If
and have opposite signs, then the root lies between and .
- If
-
Calculate the midpoint
and check the sign of : - If
has the same sign as , then the root lies in the interval . - If
has the opposite sign as , then the root lies in the interval .
- If
Let’s calculate the values of
and
to determine the sign of the function at these points.
Calculate or simplify the expression .
The values of and
are approximately 0.785388 and -0.186223, respectively.
Calculate or simplify the expression
The values of
Since
and
have opposite signs, the root of the equation
lies between
and
.
Now, we need to find the midpoint
and check the sign of
to determine the interval where the root lies.
Calculate the value by following steps:
Calculate the value by following steps:
- step0: Calculate:
- step1: Remove the parentheses:
- step2: Add the numbers:
- step3: Convert the expressions:
- step4: Multiply by the reciprocal:
- step5: Multiply the fractions:
- step6: Multiply:
Calculate or simplify the expression.
The value ofis approximately 0.307473.
Since
has the same sign as
, the root of the equation
lies in the interval
.
Therefore, the correct answer is:
a.
a.
Answered by UpStudy AI and reviewed by a Professional Tutor
Like
error msg


Bonus Knowledge
The bisection method is a robust numerical technique that continually narrows down the interval in which a root of a function exists. In the case of the equation
, starting with suitable initial endpoints is crucial. From the outputs given, it seems that the intervals suggest the method is being applied correctly. The intervals given provide a growing sense of where the function transitions from positive to negative, indicating a root.
When you apply the bisection method, always ensure that the chosen endpoints contain a sign change. This means verifying that
and
yield opposite signs. It’s common for novice users to mistakenly choose endpoints that don’t reflect a sign change, which can lead to incorrect conclusions. Always double-check those calculations!