Pregunta
Using bisection method two times on the equation
We get the end points
a.
.
ob.
.
c.
.
d. None.
We get the end points
a.
ob.
c.
d. None.
Ask by Schneider Joseph. in Egypt
Mar 25,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The correct interval after two bisection method iterations is
.
Solución
To solve the equation
using the bisection method, we need to find the interval where the function
changes sign.
Given that the end points are
and
, we can use the bisection method to find the root of the equation.
Let’s denote the function as
.
-
Check the sign of
and : -
-
Determine the sign of
and : - If
and have opposite signs, then the root lies between and .
- If
-
Calculate the midpoint
and check the sign of : - If
has the same sign as , then the root lies in the interval . - If
has the opposite sign as , then the root lies in the interval .
- If
Let’s calculate the values of
and
to determine the sign of the function at these points.
Calculate or simplify the expression .
The values of and
are approximately 0.785388 and -0.186223, respectively.
Calculate or simplify the expression
The values of
Since
and
have opposite signs, the root of the equation
lies between
and
.
Now, we need to find the midpoint
and check the sign of
to determine the interval where the root lies.
Calculate the value by following steps:
Calculate the value by following steps:
- step0: Calculate:
- step1: Remove the parentheses:
- step2: Add the numbers:
- step3: Convert the expressions:
- step4: Multiply by the reciprocal:
- step5: Multiply the fractions:
- step6: Multiply:
Calculate or simplify the expression.
The value ofis approximately 0.307473.
Since
has the same sign as
, the root of the equation
lies in the interval
.
Therefore, the correct answer is:
a.
a.
Respondido por UpStudy AI y revisado por un tutor profesional
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Bonus Knowledge
The bisection method is a robust numerical technique that continually narrows down the interval in which a root of a function exists. In the case of the equation
, starting with suitable initial endpoints is crucial. From the outputs given, it seems that the intervals suggest the method is being applied correctly. The intervals given provide a growing sense of where the function transitions from positive to negative, indicating a root.
When you apply the bisection method, always ensure that the chosen endpoints contain a sign change. This means verifying that
and
yield opposite signs. It’s common for novice users to mistakenly choose endpoints that don’t reflect a sign change, which can lead to incorrect conclusions. Always double-check those calculations!

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