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Write the first five terms of the sequence. \( f(0)=-7, f(n)=f(n-1)+8 \)

Ask by Barrett Vaughan. in the United States
Feb 26,2025

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Answer

The first five terms of the sequence are -7, 1, 9, 17, and 25.

Solution

To find the first five terms of the sequence defined by \( f(0) = -7 \) and \( f(n) = f(n-1) + 8 \), we will calculate each term step by step. 1. **First term**: \[ f(0) = -7 \] 2. **Second term**: \[ f(1) = f(0) + 8 = -7 + 8 = 1 \] 3. **Third term**: \[ f(2) = f(1) + 8 = 1 + 8 = 9 \] 4. **Fourth term**: \[ f(3) = f(2) + 8 = 9 + 8 = 17 \] 5. **Fifth term**: \[ f(4) = f(3) + 8 = 17 + 8 = 25 \] Now, we can summarize the first five terms of the sequence: - \( f(0) = -7 \) - \( f(1) = 1 \) - \( f(2) = 9 \) - \( f(3) = 17 \) - \( f(4) = 25 \) Thus, the first five terms of the sequence are: \[ -7, 1, 9, 17, 25 \]

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The first term of the sequence starts with \( f(0) = -7 \). To find the subsequent terms, we use the recursive formula \( f(n) = f(n-1) + 8 \). So, the next terms are: - \( f(1) = f(0) + 8 = -7 + 8 = 1 \) - \( f(2) = f(1) + 8 = 1 + 8 = 9 \) - \( f(3) = f(2) + 8 = 9 + 8 = 17 \) - \( f(4) = f(3) + 8 = 17 + 8 = 25 \) Thus, the first five terms of the sequence are: -7, 1, 9, 17, 25.

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