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5. Romero cut a piece of paper with a width of 4 inches and a length of 12 inches. Ulysses cut a second piece of paper that also had a length of 12 inches. Uysses wanted his piece of paper to have an area that is half the area of Romero's piece of paper. How wide will Ulysses have to cut his piece of paper?

Ask by Ross Morgan. in the United States
Feb 26,2025

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Answer

Ulysses needs to cut his paper to be 2 inches wide to have an area half of Romero's.

Solution

Romero's piece of paper has an area of 4 inches × 12 inches = 48 square inches. Ulysses wants his piece of paper, which also has a length of 12 inches, to have an area of 48/2 = 24 square inches. To find the necessary width of Ulysses' paper, let w be the width. We have: 12 inches × w = 24 square inches Dividing both sides by 12 gives: w = 24/12 = 2 inches So, Ulysses will have to cut his piece of paper with a width of 2 inches.

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To find out how wide Ulysses must cut his piece of paper, we first need to calculate the area of Romero's paper. The area of a rectangle is calculated by multiplying its width by its length. Romero's area is: 4 inches (width) x 12 inches (length) = 48 square inches. Since Ulysses wants his paper to have an area that is half of Romero's, we divide 48 by 2: 48 ÷ 2 = 24 square inches. Now, we know Ulysses's paper has a length of 12 inches and an area of 24 square inches. To find the width, we rearrange the area formula: Area = Width x Length. So, Ulysses's width: 24 square inches = Width x 12 inches. Dividing both sides by 12 gives: Width = 24 ÷ 12 = 2 inches. Thus, Ulysses must cut his piece of paper to a width of **2 inches**.

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