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Problema 1. Calcular la energía cinética que lleva una bala de 0.006 kg si su velocidad posee una magnitı \( 510 \mathrm{~m} / \mathrm{s} \). \( \begin{array}{l}\text { Datos } \\ \text { Formula } \\ \text { Operación }\end{array} \)

Ask by Lewis Crawford. in Mexico
Mar 11,2025

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La energía cinética de la bala es de aproximadamente 780.3 J.

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Para calcular la energía cinética (EC) de la bala, utilizamos la fórmula EC = (1/2)mv², donde m es la masa y v es la velocidad. Dado que m = 0.006 kg y v = 510 m/s, sustituyendo estos valores en la fórmula conseguimos: EC = (1/2) * 0.006 kg * (510 m/s)². Ahora realizamos la operación: EC = (0.003) * (260100) = 780.3 J. Por lo tanto, la energía cinética de la bala es de aproximadamente 780.3 julios. ¡Eso es un montón de energía en muy poco peso!

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