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\begin{tabular}{l} 2UESTION 1 (Whole Numbers: Add, Subtract, Multiply \& Divide) \\ \begin{tabular}{|l} Calculate the following using the Column Method \\ \hline \( 27835+32132 \) \\ \hline \( 457834-325613 \) \\ \( 14815 \times 38 \) \\ \hline\end{tabular} \\ \hline Calculate the following using any method \\ \hline 2642\end{tabular}

Ask by Allan Santiago. in South Africa
Mar 12,2025

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Answer

Here are the results: 1. \( 27835 + 32132 = 59967 \) 2. \( 457834 - 325613 = 132221 \) 3. \( 14815 \times 38 = 562970 \) 4. \( 2642 = 2642 \)

Solution

Let's solve the problems step by step using the column method for addition and subtraction, and then we will perform multiplication. Finally, we will calculate the last number using any method. ### 1. Addition: \( 27835 + 32132 \) We will align the numbers by their rightmost digits and add them column by column. ``` 27835 + 32132 -------- ``` Starting from the rightmost column: - **Units place:** \( 5 + 2 = 7 \) - **Tens place:** \( 3 + 3 = 6 \) - **Hundreds place:** \( 8 + 1 = 9 \) - **Thousands place:** \( 7 + 2 = 9 \) - **Ten-thousands place:** \( 2 + 3 = 5 \) So, the result is: \[ 27835 + 32132 = 59967 \] ### 2. Subtraction: \( 457834 - 325613 \) Align the numbers for subtraction: ``` 457834 - 325613 -------- ``` Starting from the rightmost column: - **Units place:** \( 4 - 3 = 1 \) - **Tens place:** \( 3 - 1 = 2 \) - **Hundreds place:** \( 8 - 6 = 2 \) - **Thousands place:** \( 7 - 5 = 2 \) - **Ten-thousands place:** \( 5 - 2 = 3 \) - **Hundred-thousands place:** \( 4 - 3 = 1 \) So, the result is: \[ 457834 - 325613 = 132221 \] ### 3. Multiplication: \( 14815 \times 38 \) We can break this down using the distributive property: \[ 14815 \times 38 = 14815 \times (30 + 8) = 14815 \times 30 + 14815 \times 8 \] Calculating each part: - \( 14815 \times 30 = 444450 \) - \( 14815 \times 8 = 118520 \) Now, add these two results: \[ 444450 + 118520 = 562970 \] So, the result is: \[ 14815 \times 38 = 562970 \] ### 4. Calculate \( 2642 \) Since no specific operation is mentioned for \( 2642 \), we can simply state it as is: \[ 2642 \] ### Summary of Results 1. \( 27835 + 32132 = 59967 \) 2. \( 457834 - 325613 = 132221 \) 3. \( 14815 \times 38 = 562970 \) 4. \( 2642 = 2642 \) These are the final results for the calculations.

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To calculate \( 27835 + 32132 \) using the Column Method, align the numbers vertically by their place values: ``` 27835 + 32132 ------- 59967 ``` So, \( 27835 + 32132 = 59967 \). For \( 457834 - 325613 \): ``` 457834 - 325613 --------- 132221 ``` Thus, \( 457834 - 325613 = 132221 \). Next, for \( 14815 \times 38 \), let's multiply: ``` 14815 x 38 --------- 118520 (14815 x 8) +44445 (14815 x 30, shifted one position left) --------- 56270 ``` Therefore, \( 14815 \times 38 = 56270 \). Now for \( 2642 \) using any method, we can simply state the number as it is. So, \( 2642 \) is already calculated!

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