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Factor completely. \[ 64-49 x^{2} \]

Ask by Lee Bryant. in the United States
Mar 14,2025

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The expression \( 64 - 49x^{2} \) factors to \( (8 - 7x)(8 + 7x) \).

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To factor the expression \( 64 - 49x^2 \), we can recognize it as a difference of two squares. It can be written as: \[ 8^2 - (7x)^2 \] According to the difference of squares formula, \( a^2 - b^2 = (a - b)(a + b) \), we can apply it here: \[ (8 - 7x)(8 + 7x) \] So, the complete factorization of \( 64 - 49x^2 \) is: \[ (8 - 7x)(8 + 7x) \] And there you go—your expression is now completely factored!

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