Question

2. Find the \( 90 \% \) confidence interval if there are 85 employees taken the same work with a mean of 180 and standard deviation of 40.

Ask by Ortega Cervantes. in the Philippines
Mar 19,2025

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Answer

The \( 90\% \) confidence interval for the mean is approximately \( 172.86 \) to \( 187.14 \).

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To calculate the 90% confidence interval, you can use the formula: \[ \text{Confidence Interval} = \bar{x} \pm z \left( \frac{s}{\sqrt{n}} \right) \] Where: - \(\bar{x}\) is the sample mean (180), - \(s\) is the standard deviation (40), - \(n\) is the sample size (85), - \(z\) is the z-score corresponding to the desired confidence level. For a 90% confidence level, the z-score is approximately 1.645. Now, plug in the values: \[ \text{Margin of Error} = 1.645 \left( \frac{40}{\sqrt{85}} \right) \approx 1.645 \times 4.33 \approx 7.11 \] Thus, the confidence interval is: \[ 180 \pm 7.11 \] This gives us: \[ (172.89, 187.11) \] So, the 90% confidence interval is approximately \( (172.89, 187.11) \).

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