At ABC shop, 3 hamburgers and 2 cooldrinks cost R89, whereas 2 hamburgers and 3 cooldrinks cost R73,50. Determine the cost of 1 hamburger.

Question

UpStudy AI · Accepted Answer

Let $$ h $$ denote the cost of one hamburger and $$ c $$ denote the cost of one cooldrink.

We are given:
$$
3h + 2c = 89
$$
$$
2h + 3c = 73.5
$$

**Step 1. Eliminate one variable**

Multiply the first equation by $$ 3 $$ and the second equation by $$ 2 $$ so both equations have the same coefficient for $$ c $$:
$$
3(3h + 2c) \implies 9h + 6c = 267
$$
$$
2(2h + 3c) \implies 4h + 6c = 147
$$

**Step 2. Subtract the equations**

Subtract the second new equation from the first new equation:
$$
(9h + 6c) - (4h + 6c) = 267 - 147
$$
$$
5h = 120
$$

**Step 3. Solve for $$ h $$**

Divide both sides by $$ 5 $$:
$$
h = \frac{120}{5} = 24
$$

Thus, the cost of one hamburger is $$ \textbf{R24} $$.
The cost of one hamburger is R24.

At ABC shop, 3 hamburgers and 2 cooldrinks cost R89, whereas 2 hamburgers and 3 cooldrinks cost R73,50. Determine the cost of 1 hamburger.

Upstudy AI Solution

Answer

Solution

The Deep Dive

Related Questions

Latest Algebra Questions