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Solve the quadratic formula to solve \( 9 x^{2}=-12 x+2 \). \[ x=\square \]

Ask by Savage Morgan. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

The solutions are \( x = -\frac{2+\sqrt{6}}{3} \) and \( x = \frac{-2+\sqrt{6}}{3} \).

Solution

Solve the equation \( 9x^2=-12x+2 \). Solve the quadratic equation by following steps: - step0: Solve using the quadratic formula: \(9x^{2}=-12x+2\) - step1: Move the expression to the left side: \(9x^{2}+12x-2=0\) - step2: Solve using the quadratic formula: \(x=\frac{-12\pm \sqrt{12^{2}-4\times 9\left(-2\right)}}{2\times 9}\) - step3: Simplify the expression: \(x=\frac{-12\pm \sqrt{12^{2}-4\times 9\left(-2\right)}}{18}\) - step4: Simplify the expression: \(x=\frac{-12\pm \sqrt{216}}{18}\) - step5: Simplify the expression: \(x=\frac{-12\pm 6\sqrt{6}}{18}\) - step6: Separate into possible cases: \(\begin{align}&x=\frac{-12+6\sqrt{6}}{18}\\&x=\frac{-12-6\sqrt{6}}{18}\end{align}\) - step7: Simplify the expression: \(\begin{align}&x=\frac{-2+\sqrt{6}}{3}\\&x=\frac{-12-6\sqrt{6}}{18}\end{align}\) - step8: Simplify the expression: \(\begin{align}&x=\frac{-2+\sqrt{6}}{3}\\&x=-\frac{2+\sqrt{6}}{3}\end{align}\) - step9: Rewrite: \(x_{1}=-\frac{2+\sqrt{6}}{3},x_{2}=\frac{-2+\sqrt{6}}{3}\) The solutions to the quadratic equation \(9x^{2}=-12x+2\) are \(x_{1}=-\frac{2+\sqrt{6}}{3}\) and \(x_{2}=\frac{-2+\sqrt{6}}{3}\).

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Mind Expander

Let's rewrite the equation in standard form. Start by moving all terms to one side: \[ 9x^{2} + 12x - 2 = 0. \] Now we can use the quadratic formula, \( x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \), where \( a = 9 \), \( b = 12 \), and \( c = -2 \). First, calculate the discriminant: \[ b^2 - 4ac = 12^2 - 4(9)(-2) = 144 + 72 = 216. \] Now, plug the values into the quadratic formula: \[ x = \frac{-12 \pm \sqrt{216}}{2(9)}. \] Since \( \sqrt{216} = 6\sqrt{6} \), the equation simplifies to: \[ x = \frac{-12 \pm 6\sqrt{6}}{18}. \] This reduces to: \[ x = \frac{-2 \pm \sqrt{6}}{3}. \] So the solutions are: \[ x = \frac{-2 + \sqrt{6}}{3} \quad \text{and} \quad x = \frac{-2 - \sqrt{6}}{3}. \]

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