Solve the quadratic formula to solve \( 9 x^{2}=-12 x+2 \). \[ x=\square \]
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Let's rewrite the equation in standard form. Start by moving all terms to one side: \[ 9x^{2} + 12x - 2 = 0. \] Now we can use the quadratic formula, \( x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a} \), where \( a = 9 \), \( b = 12 \), and \( c = -2 \). First, calculate the discriminant: \[ b^2 - 4ac = 12^2 - 4(9)(-2) = 144 + 72 = 216. \] Now, plug the values into the quadratic formula: \[ x = \frac{-12 \pm \sqrt{216}}{2(9)}. \] Since \( \sqrt{216} = 6\sqrt{6} \), the equation simplifies to: \[ x = \frac{-12 \pm 6\sqrt{6}}{18}. \] This reduces to: \[ x = \frac{-2 \pm \sqrt{6}}{3}. \] So the solutions are: \[ x = \frac{-2 + \sqrt{6}}{3} \quad \text{and} \quad x = \frac{-2 - \sqrt{6}}{3}. \]