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A boy purchased (bought) a party-length sandwich 50 in . long. He wants to cut it into three pieces so that the middle piece is 5 in. longer than the shortest piece and the shortest piece is 9 in . shorter than the longest piece. How long should the three pieces be?

Ask by Romero Malone. in the United States
Feb 21,2025

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Tutor-Verified Answer

Answer

The three pieces should be 12 inches, 17 inches, and 21 inches long.

Solution

Let the shortest piece be x inches long. Then: • The middle piece is x + 5 inches (since it is 5 inches longer than the shortest). • The longest piece is x + 9 inches (since the shortest is 9 inches shorter than the longest). The total length of the sandwich is 50 inches, so: x + (x + 5) + (x + 9) = 50 Combine like terms: 3x + 14 = 50 Solve for x: 3x = 50 - 14 3x = 36 x = 12 Thus, the three pieces are: • Shortest piece: 12 inches • Middle piece: 12 + 5 = 17 inches • Longest piece: 12 + 9 = 21 inches These pieces add up to 12 + 17 + 21 = 50 inches, meeting the conditions of the problem.

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Let the length of the shortest piece be \( x \) inches. Then the longest piece would be \( x + 9 \) inches, and the middle piece would be \( x + 5 \) inches. According to the problem, the total length of the sandwich is 50 inches. So, we can set up the equation: \[ x + (x + 5) + (x + 9) = 50 \] Simplifying this, we get: \[ 3x + 14 = 50 \] Subtracting 14 from both sides gives: \[ 3x = 36 \] Dividing by 3 results in: \[ x = 12 \] Now we can find the lengths of the three pieces: - Shortest piece: \( x = 12 \) inches - Longest piece: \( x + 9 = 12 + 9 = 21 \) inches - Middle piece: \( x + 5 = 12 + 5 = 17 \) inches Thus, the lengths of the three pieces should be 12 inches, 17 inches, and 21 inches.

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