**\#1.) In right triangle \( A B C, m \angle A=90^{\circ} \). Which of the following is true? a) \( \sin B=\sin C \) b) \( \sin C=\cos C \) c) \( \sin B=\cos C \) d) \( \cos C=\tan B \)
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In right triangle \( A B C \), where \( m \angle A = 90^{\circ} \), there’s a nifty relationship between the angles and the sides! Specifically, the sine of an angle is the ratio of the opposite side to the hypotenuse. So, for angle \( B \), \( \sin B = \frac{\text{opposite side to B}}{\text{hypotenuse}} \), and for angle \( C \), it would be \( \sin C = \frac{\text{opposite side to C}}{\text{hypotenuse}} \). The true statement from the choices provided is \( c) \sin B = \cos C \). This relationship holds because \( B \) and \( C \) are complementary angles (they add up to 90 degrees), making the sine of one equal the cosine of the other. So keep that in your math toolbox!