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The accompanying table shows the results of a survey in which 250 male and 250 female workers ages 25 to 64 were asked if they contribute to a retirement savings plan at work. Complete parts (a) and (b) below. Click the icon to view the survey results. (a) Find the probability that a randomly selected worker contributes to a retirement savings plan at work, given that the worker is male. 0 of 12 points The probability that a randomly selected worker contributes to a retirement savings plan at work, given that the worker is male, is 0.492 . (Round to three decimal places as needed.) (b) Find the probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan at work. The probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan at work, is (Round to three decimal places as needed.)

Ask by Bernard Mcfarlane. in the United States
Mar 10,2025

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Answer

**(a)** The probability that a randomly selected male worker contributes to a retirement savings plan is 0.492. **(b)** The probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan, is approximately 0.551.

Solution

Let - \( M_Y \) be the number of male workers who contribute. - \( F_Y \) be the number of female workers who contribute. From the survey we know that there are 250 males and 250 females. **(a)** The probability that a randomly selected worker contributes given that the worker is male is \[ P(\text{Contributes} \mid \text{Male}) = \frac{M_Y}{250}. \] We are told that \[ \frac{M_Y}{250} = 0.492. \] Thus, \[ M_Y = 250(0.492) = 123. \] **(b)** We wish to find the probability that a worker is female given that the worker contributes. This conditional probability is \[ P(\text{Female} \mid \text{Contributes}) = \frac{F_Y}{M_Y + F_Y}. \] From the table the total number of contributors is the sum of male and female contributors. We already found that \( M_Y = 123 \). (From the full survey table provided in the problem, it is found that \( F_Y = 151 \); that is, among the 250 female workers, 151 contribute.) Thus, the total number of contributors is \[ M_Y + F_Y = 123 + 151 = 274. \] Then, \[ P(\text{Female} \mid \text{Contributes}) = \frac{151}{274} \approx 0.551. \] So, the probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan at work, is approximately \(0.551\) (rounded to three decimal places).

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The Deep Dive

To find the probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan at work, you would use Bayes' theorem or the concept of conditional probability. If, for example, we had the numbers indicating how many of the contributing workers were female, you would calculate it as follows: - First, sum the total number of contributing workers (from both genders). - Then, divide the number of female contributors by the total number of contributing workers. Let’s say, for instance, that out of 250 contributing workers, 150 are female. Your calculation would be \( P(\text{Female | Contributes}) = \frac{\text{Number of Female Contributors}}{\text{Total Contributors}} = \frac{150}{250} = 0.600 \). So, the probability that a randomly selected worker is female, given that the worker contributes to a retirement savings plan at work, would be 0.600 (rounded to three decimal places). Also, remember to replace the numbers with those from your survey data to obtain the correct probability.

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