Current learning objective: z-Scores Question 20 Score: 0 of 4 points Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the \( z \)-score of a man 76.9 inches tall. Round your answer to 2 decimal places.

To find the \( z \)-score of a man who is 76.9 inches tall, you'll need to use the formula: \[ z = \frac{(X - \mu)}{\sigma} \] Where: - \( X \) is the value you're examining (76.9 inches), - \( \mu \) is the mean (69.0 inches), - \( \sigma \) is the standard deviation (2.8 inches). Plug in the numbers: \[ z = \frac{(76.9 - 69.0)}{2.8} = \frac{7.9}{2.8} \approx 2.82 \] So, the \( z \)-score for a man who is 76.9 inches tall is approximately 2.82 when rounded to two decimal places! Keep in mind that a \( z \)-score of 2.82 indicates that this man is 2.82 standard deviations above the average height for adult men.