\( 10(5.1,5.2) \) A baseball player hit 61 home runs in a season. Of the 61 home runs, 21 went to right field, 17 went to right center field, 11 went to center field, 10 went to left center field, and 2 went to left field. (a) What is the probability that a randomly selected home run was hit to right field? \( 20,5.1 \times 1 \), Points: 0 of 1 (b) What is the probability that a randomly selected home run was hit to left field? (c) Was it unusual for this player to hit a home run to leff field? Explain. (a) The probability that a randomly selected home run was hit to right field is 0.344 . (Round to three decimal places as needed.) (b) The probability that a randomly selected home run was hit to left field is (Round to three decimal places as needed.)

To find the probability that a randomly selected home run was hit to left field, use the formula for probability: \[ P(\text{Left Field}) = \frac{\text{Number of home runs to left field}}{\text{Total number of home runs}} = \frac{2}{61} \] Calculating that gives: \[ P(\text{Left Field}) \approx 0.033 \] So, the probability that a randomly selected home run was hit to left field is approximately 0.033 (rounded to three decimal places). Now, was it unusual for this player to hit a home run to left field? Generally, an event is considered unusual if its probability is less than 0.05. Since the probability of hitting a home run to left field is about 0.033, which is less than 0.05, it can be deemed unusual for this player to hit a home run to left field.