A function is given. \( f(x)=5-3 x^{2} ; \quad x=4, x=4+h \) (a) Determine the net change between the given values of the variable. (b) Determine the average rate of change between the given values of the variable. (b)
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To find the net change of the function \( f(x) = 5 - 3x^2 \) between \( x = 4 \) and \( x = 4 + h \): (a) First, we calculate \( f(4) \) and \( f(4 + h) \): - \( f(4) = 5 - 3(4^2) = 5 - 48 = -43 \) - \( f(4 + h) = 5 - 3(4 + h)^2 = 5 - 3(16 + 8h + h^2) = 5 - 48 - 24h - 3h^2 = -43 - 24h - 3h^2 \) Now, the net change is: \[ \Delta f = f(4 + h) - f(4) = (-43 - 24h - 3h^2) - (-43) = -24h - 3h^2 \] (b) The average rate of change between \( x = 4 \) and \( x = 4 + h \) is given by: \[ \text{Average Rate of Change} = \frac{f(4 + h) - f(4)}{(4 + h) - 4} = \frac{-24h - 3h^2}{h} = -24 - 3h \] So, the answers are: (a) The net change is \( -24h - 3h^2 \). (b) The average rate of change is \( -24 - 3h \).