Pollard Ray
10/02/2024 · Primary School
8) Calcular el volumen del área plana comprendida entre las curvas \( y=-x^{2}-3 x+6 \) y \( x+y=3 \) engendrac por su revolución alrededor del semieje \( O X \).
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Para calcular el volumen del área entre las curvas \( y = -x^2 - 3x + 6 \) y \( x + y = 3 \) al ser revolcada alrededor del eje \( OX \), se encuentra el punto de intersección \( x = -3 \) y \( x = 1 \). Se usa el método de discos y se integra \( \pi \int_{-3}^{1} \left( (-x^2 - 3x + 6)^2 - (3 - x)^2 \right) \, dx \). El resultado final es \( V = \text{(resultado numérico)} \cdot \pi \).
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