Haynes Griffiths
05/12/2023 · High School

20 Sia dato un triangolo \( A B C \); prolunga la mediana \( A M \), dalla parte di \( M \), di un segmento \( M D \cong A M \). Dimostra che i triangoli \( A M C \) e \( B M D \) sono congruenti.

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I triangoli \( A M C \) e \( B M D \) sono congruenti perché \( AM = MD \), \( MC = BM \), e \( \angle AMC = \angle BMD \).

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