Решите уравнение, используя введение новой переменноі а) \( \left(x^{2}+6 x\right)^{2}-5\left(x^{2}+6 x\right)=24 ; \) б) \( \left(x^{2}-2 x-5\right)^{2}-2\left(x^{2}-2 x-5\right)=3 \) -в) \( \left(x^{2}+3 x-25\right)^{2}-2\left(x^{2}+3 x-25\right)=-7 ; \) -г) \( (y+2)^{4}-(y+2)^{2}=12 ; \) д) \( \left(x^{2}+2 x\right)\left(x^{2}+2 x+2\right)=3 ; \) е) \( \left(x^{2}-x-16\right)\left(x^{2}-x+2\right)=88 ; \) -ж) \( \left(2 x^{2}+7 x-8\right)\left(2 x^{2}+7 x-3\right)-6=0 \)

Solve the system of quadratic inequalities: \[ y>x^{2}-1 \]

The polynomial of degree \( 4, P(x) \), has a root of multiplicity 2 at \( x=3 \) and roots of multiplicity 1 at \( x=0 \) and \( x=-1 \). It goes through the point \( (5,12) \). Find a formula for \( P(x) \). \( P(x)=\square \)

Solve the system of quadratic inequalities: \[ \begin{array}{l}y<x^{2}-4 \\ y>-x^{2}+2\end{array} \]

Find the points of intersection for the system \[ \begin{array}{l}\mathrm{y} \geq 2 \mathrm{x}^{2}+3 \mathrm{x}-20 \\ \mathrm{y} \leq \mathrm{x}^{2}+\mathrm{x}-5\end{array} \]

Which graph represents the solution to the system of quadratic inequalities? \( y \geq \mathrm{x}^{2}+3 \mathrm{x}-7 \) \( \mathrm{y} \leq-\mathrm{x}^{2}+5 \mathrm{x}+2 \)