Huff Phillips
03/22/2024 · Primary School

6. La siguiente reacción tiene una \( K_{\mathrm{c}}=55.3 \) a 700 K , \[ \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) \] En un matraz de 2 litros que contiene una mezcla en equilibrio de los tres gases hay 0.056 de \( \mathrm{H}_{2} \) y 4.36 g de \( \mathrm{I}_{2} \) ¿Cuántos gramos de HI hay en el matraz?

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Para calcular la masa de HI, primero determinamos la concentración de HI en equilibrio, que es aproximadamente 0.0355 mol/L. Luego, multiplicamos esta concentración por el volumen del matraz (2 litros) para obtener la cantidad total de HI en mol, y finalmente, multiplicamos esta cantidad por la masa molar de HI (molaridad de HI). La masa molar de HI es 128.0 g/mol. Por lo tanto, la masa de HI es aproximadamente \( 0.0355 \, \text{mol/L} \times 2 \, \text{L} \times 128.0 \, \text{g/mol} = 4.5952 \, \text{g} \).

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