girl-logo

Ask Questions

Mathematics Questions & Answers

Q:
Solve the equation \( \log _{7}(3 v+10)=0 .(1 \) point \( ) \) \( v=\square \)
Q:
1. \( 9 \times 5= \)
Q:
Exercices 13: Soit \( \left(u_{n}\right) \) la suite définie pour tout entier \( n \geqslant 1 \) par \( u_{n}=\frac{2^{n}}{n} \) 1. Calculer \( \frac{u_{n+1}}{u_{n}} \). 2. Résoudre l'inéquation \( \frac{2 n}{n+1}>1 \) 3. En déduire les variations de la suite \( \left(u_{n}\right) \).
Q:
a. \( \left\{\begin{array}{l}y=-x+3 \\ y=x-3\end{array}\right. \)
Q:
Solve using the quadratic formula. \[ \begin{array}{l}x^{2}+4 x=-12 \\ \text { Select the correct choice below and, if necessary, fill in the answer box within your choice. } \\ \text { A. } x=\square \\ \text { (Simplify your answer. Use a comma to separate answers as needed.) } \\ \text { B. There are no real solutions. }\end{array} \text {. } \]
Q:
\begin{tabular}{l|l} Determine whether \( (1,-4) \) is a \\ solution of \( 6 x+4 y=3 \)\end{tabular}\( | \begin{array}{l}\text { Is }(1,-4) \text { a solution to } \\ \text { the equation? } \\ \text { No }\end{array} \)
Q:
Expand the logarithm \( \ln \left(\frac{13}{x}\right) \cdot(1 \) point) \( \begin{array}{l}13-x \\ \ln (13-x) \\ \ln 13-\ln x \\ \frac{\ln 13}{\ln x}\end{array} \)
Q:
Racionalizar el denominador y simplificar. \[ \frac{2}{3 \sqrt{v}-6} \] Asumimos que la variable representa un número real positivo.
Q:
2. Una persona de 2 m de estatura divisa lo alto de una torre de altura de 32 m con un ángulo de elevación de \( 15^{\circ} \). Se acerca una distancia " \( x \) y el ángulo de elevación se duplica. ¿Cuánto vale " \( x \) "?
Q:
Write this ratio as a fraction in lowest terms. 60 minutes to 50 minutes 60 minutes to 50 minutes is (Simplify your answer. Type a fraction.)
27 28 29 30 31 32 33 34 35 36
Ask Tutors
Ask AI
10x
Fastest way to Get Answers & Solutions
By text

Enter your question here…

By image
Re-Upload
Uploaded Files
xxxx.png0%
Submit
📸 STUDY CAN BE A REAL STRUGGLE
Why Not UpStudy It?
Select your plan below
Premium

You can enjoy

  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to answer and
    solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic
  • Limited Solutions