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How many times greater is the intensity of sound from a concert speaker at a distance of 1 meter than the intensity at a distance of 5 meters?

Ask by Barber Mann. in the United States
Mar 12,2025

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Answer

The intensity of sound at 1 meter is 25 times greater than at 5 meters.

Solution

Let the intensity \( I \) be inversely proportional to the square of the distance \( r \), i.e., \[ I \propto \frac{1}{r^2}. \] At a distance of 1 meter, the intensity is \[ I(1) \propto \frac{1}{1^2} = 1. \] At a distance of 5 meters, the intensity is \[ I(5) \propto \frac{1}{5^2} = \frac{1}{25}. \] The ratio of the intensity at 1 meter to the intensity at 5 meters is \[ \frac{I(1)}{I(5)} = \frac{1}{\frac{1}{25}} = 25. \] Thus, the intensity of sound from the concert speaker at 1 meter is \( 25 \) times greater than the intensity at 5 meters.

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The intensity of sound diminishes with distance due to the inverse square law, which states that intensity is inversely proportional to the square of the distance from the source. So if you're 1 meter away, the intensity is \( I_1 \) and at 5 meters, it’s \( I_5 \). The ratio of intensities is given by: \[ \frac{I_1}{I_5} = \left(\frac{d_5}{d_1}\right)^2 = \left(\frac{5}{1}\right)^2 = 25 \] Thus, the intensity of sound from a concert speaker at a distance of 1 meter is 25 times greater than the intensity at a distance of 5 meters. Now that's loud enough to make you want to dance! But remember, getting too close to those speakers can turn that dance into a hearing health issue! Enjoy the music but protect your ears!

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