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\( 1 \leftarrow \) Find both the exact and ordinary interest on \( \$ 35,800 \) at \( 9 \frac{1}{4} \% \) for 158 days. Then find the amount by which the ordinary interest is larger. The exact interest on \( \$ 35,800 \) at \( 9 \frac{1}{4} \% \) for 158 days is \( \$ \square \). (Round to the nearest cent.) The ordinary interest on \( \$ 35,800 \) at \( 9 \frac{1}{4} \% \) for 158 days is \( \$ \square \). (Round to the nearest cent.) The amount by which the ordinary interest is larger is \( \$ \square \).

Ask by Osborne Mccoy. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

Exact interest: \$1,433.47 Ordinary interest: \$1,453.38 Difference: \$19.91

Solution

Let \[ P=\$35\,800,\quad r=9.25\% = 0.0925,\quad t=158\text{ days}. \] For the exact interest we use 365 days per year. The formula for simple interest is \[ I=P\cdot r\cdot \frac{t}{365}. \] **Step 1. Exact Interest** Compute \[ I_{\text{exact}} = 35\,800\cdot 0.0925\cdot \frac{158}{365}. \] First, calculate \[ 35\,800\cdot 0.0925 = 3\,311.50. \] Then, \[ I_{\text{exact}} = 3\,311.50\cdot \frac{158}{365} = \frac{3\,311.50\times 158}{365}. \] Multiplying the numerator, \[ 3\,311.50\times 158 = 523\,217. \] Thus, \[ I_{\text{exact}} = \frac{523\,217}{365}\approx 1\,433.47. \] So, the exact interest is \(\$1\,433.47\). --- **Step 2. Ordinary Interest** For ordinary interest, a 360-day year is assumed. The formula is \[ I_{\text{ord}}=P\cdot r\cdot \frac{t}{360}. \] Compute \[ I_{\text{ord}} = 35\,800\cdot 0.0925\cdot \frac{158}{360}. \] We already have \[ 35\,800\cdot 0.0925 = 3\,311.50. \] Then, \[ I_{\text{ord}} = 3\,311.50\cdot \frac{158}{360} = \frac{3\,311.50\times 158}{360}. \] The numerator is the same: \[ 3\,311.50\times 158 = 523\,217. \] Thus, \[ I_{\text{ord}} = \frac{523\,217}{360}\approx 1\,453.38. \] So, the ordinary interest is \(\$1\,453.38\). --- **Step 3. Difference** The ordinary interest exceeds the exact interest by \[ \Delta I = I_{\text{ord}} - I_{\text{exact}} \approx 1\,453.38 - 1\,433.47 \approx 19.91. \] --- **Final Answers:** Exact interest: \(\$1\,433.47\). Ordinary interest: \(\$1\,453.38\). Amount by which the ordinary interest is larger: \(\$19.91\).

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To solve the problem, we'll first calculate both the exact interest and ordinary interest for the given amount and time frame. 1. **Calculating Exact Interest:** The formula for exact interest is: \[ I = P \times r \times t \] where: - \( P = 35,800 \) - \( r = \frac{9.25}{100} = 0.0925 \) - \( t = \frac{158}{365} \) (since there are 365 days in a year for exact interest) So, \[ I = 35,800 \times 0.0925 \times \frac{158}{365} \approx 35,800 \times 0.0925 \times 0.4328767 \approx 1,488.69 \] Thus, the exact interest is approximately **$1,488.69**. 2. **Calculating Ordinary Interest:** The formula for ordinary interest is similar, but it uses 360 days for the year: \[ I = P \times r \times t \] where \( t = \frac{158}{360} \). So, \[ I = 35,800 \times 0.0925 \times \frac{158}{360} \approx 35,800 \times 0.0925 \times 0.4388889 \approx 1,452.56 \] Thus, the ordinary interest is approximately **$1,452.56**. 3. **Calculating the Difference:** To find by how much the ordinary interest is larger than the exact interest: \[ \text{Difference} = \text{Ordinary Interest} - \text{Exact Interest} \] \[ \text{Difference} = 1,452.56 - 1,488.69 \approx -36.13 \] Thus, the amount by which the ordinary interest is larger is approximately **-$36.13** (indicating that exact interest is actually larger). Final answers: - The exact interest on \( \$ 35,800 \) at \( 9 \frac{1}{4} \% \) for 158 days is \( \$ 1,488.69 \). - The ordinary interest on \( \$ 35,800 \) at \( 9 \frac{1}{4} \% \) for 158 days is \( \$ 1,452.56 \). - The amount by which the ordinary interest is larger is \( \$ -36.13 \).

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