Determine the amplitude, period, and phase shift (if any) of the given function. Graph the function. \( y=-2 \sin x \) The amplitude is \( \begin{array}{l}\text { (Simplify your answer. Type an } \\ \text { exact answer, using } \pi \text { as needed.) }\end{array} \)
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The Deep Dive
The amplitude of the function \( y = -2 \sin x \) is given by the absolute value of the coefficient in front of the sine function. Here, the coefficient is -2, resulting in an amplitude of \( |{-2}| = 2 \). The period of the sine function is typically \( 2\pi \). Since there are no modifications to the \( x \) variable (like a coefficient that would stretch or compress), the period remains \( 2\pi \). Finally, there is no phase shift in this equation, as there are no additions or subtractions inside the sine function to adjust its position along the x-axis. In summary: - Amplitude: 2 - Period: \( 2\pi \) - Phase shift: 0 To visualize this function, you would graph the sine wave reflected across the x-axis (due to the negative sign) but maintaining the amplitude of 2. It would oscillate between 2 and -2 over each interval of \( 2\pi \).