b) \( x^{2}-15 x+56= \)

To tackle the equation \( x^{2}-15x+56=0 \), you first look for two numbers that multiply to 56 and add to -15. Those numbers are -7 and -8! This means you can factor the equation as \( (x - 7)(x - 8) = 0 \). Solving for x gives you x = 7 and x = 8! Now, if you're looking to apply this quadratic factorization in real-world situations, think about projectile motion or economics! For example, when modeling the trajectory of a ball kicked into the air, the height can be expressed as a quadratic equation. Understanding where this height is zero (the ground) helps players gauge the ball's path and make better game decisions!