Brent Pickett borrowed \( \$ 8000 \) from his brother Dave. He agreed to repay the money at the end of 2 years, giving Dave the same amount of interest that he would have received if the money had been invested at \( 1.25 \% \) compounded quarterly. How much money did Brent repay his brother? Brent repaid his brother \( \$ \square \). (Round to the nearest cent as needed.)
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To calculate how much money Brent repaid his brother, we first need to find out how much interest Dave would earn if he invested the \$8000 at 1.25% interest compounded quarterly for 2 years. The formula for compound interest is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the number of years the money is invested or borrowed. In this case: - \( P = 8000 \) - \( r = 0.0125 \) (1.25% as a decimal) - \( n = 4 \) (quarterly) - \( t = 2 \) Plugging in the values, we have: \[ A = 8000 \left(1 + \frac{0.0125}{4}\right)^{4 \times 2} \] Calculating it step by step: 1. Calculate \( \frac{0.0125}{4} = 0.003125 \). 2. So, \( A = 8000 \left(1 + 0.003125\right)^{8} \). 3. Then, calculate \( 1 + 0.003125 = 1.003125 \). 4. Now, \( A = 8000 \left(1.003125\right)^{8} \). 5. Calculating \( (1.003125)^{8} \approx 1.025089 \). 6. Finally, \( A \approx 8000 \times 1.025089 \approx 8200.71 \). The total amount (including the principal) that Brent repaid his brother is approximately \$8200.71. Brent repaid his brother \( \$ 8200.71 \).