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Brent Pickett borrowed \( \$ 8000 \) from his brother Dave. He agreed to repay the money at the end of 2 years, giving Dave the same amount of interest that he would have received if the money had been invested at \( 1.25 \% \) compounded quarterly. How much money did Brent repay his brother? Brent repaid his brother \( \$ \square \). (Round to the nearest cent as needed.)

Ask by Pritchard Knight. in the United States
Mar 09,2025

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Answer

Brent repaid his brother \$8,202.20.

Solution

To solve this problem, we need to calculate the amount of money Brent repaid his brother, which includes the principal amount borrowed and the interest earned. Given: - Principal amount borrowed = $8000 - Interest rate = 1.25% compounded quarterly - Time period = 2 years First, we need to calculate the interest earned if the money had been invested at 1.25% compounded quarterly for 2 years. The formula for compound interest is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount. - \( r \) is the annual interest rate (in decimal form). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the time the money is invested for in years. In this case, the interest rate is 1.25% or 0.0125 in decimal form, and the money is compounded quarterly, so \( n = 4 \) and \( t = 2 \) years. Substitute the values into the formula to calculate the interest earned: \[ A = 8000 \left(1 + \frac{0.0125}{4}\right)^{4 \times 2} \] Now, we can calculate the amount of money Brent repaid his brother by adding the principal amount and the interest earned. Calculate the value by following steps: - step0: Calculate: \(8000\left(1+\frac{0.0125}{4}\right)^{4\times 2}\) - step1: Divide the terms: \(8000\left(1+\frac{1}{320}\right)^{4\times 2}\) - step2: Add the numbers: \(8000\left(\frac{321}{320}\right)^{4\times 2}\) - step3: Multiply the numbers: \(8000\left(\frac{321}{320}\right)^{8}\) - step4: Simplify: \(8000\times \frac{321^{8}}{320^{8}}\) - step5: Rewrite the expression: \(320\times 25\times \frac{321^{8}}{320^{8}}\) - step6: Reduce the numbers: \(25\times \frac{321^{8}}{320^{7}}\) - step7: Rewrite the expression: \(25\times \frac{321^{8}}{5^{7}\times 64^{7}}\) - step8: Rewrite the expression: \(5^{2}\times \frac{321^{8}}{5^{7}\times 64^{7}}\) - step9: Reduce the numbers: \(1\times \frac{321^{8}}{5^{5}\times 64^{7}}\) - step10: Multiply the fractions: \(\frac{321^{8}}{3125\times 64^{7}}\) The interest earned if the money had been invested at 1.25% compounded quarterly for 2 years is approximately $8202.20. Therefore, Brent repaid his brother $8202.20.

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Beyond the Answer

To calculate how much money Brent repaid his brother, we first need to find out how much interest Dave would earn if he invested the \$8000 at 1.25% interest compounded quarterly for 2 years. The formula for compound interest is: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial amount of money). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the number of years the money is invested or borrowed. In this case: - \( P = 8000 \) - \( r = 0.0125 \) (1.25% as a decimal) - \( n = 4 \) (quarterly) - \( t = 2 \) Plugging in the values, we have: \[ A = 8000 \left(1 + \frac{0.0125}{4}\right)^{4 \times 2} \] Calculating it step by step: 1. Calculate \( \frac{0.0125}{4} = 0.003125 \). 2. So, \( A = 8000 \left(1 + 0.003125\right)^{8} \). 3. Then, calculate \( 1 + 0.003125 = 1.003125 \). 4. Now, \( A = 8000 \left(1.003125\right)^{8} \). 5. Calculating \( (1.003125)^{8} \approx 1.025089 \). 6. Finally, \( A \approx 8000 \times 1.025089 \approx 8200.71 \). The total amount (including the principal) that Brent repaid his brother is approximately \$8200.71. Brent repaid his brother \( \$ 8200.71 \).

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