Question
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K) \( \left(\frac{x}{3}+\frac{y}{5}\right)^{2} \)

Ask by Mathis Young. in Brazil
Mar 11,2025

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Answer

A expressão \( \left(\frac{x}{3}+\frac{y}{5}\right)^{2} \) simplificada é \( \frac{x^{2}}{9} + \frac{2xy}{15} + \frac{y^{2}}{25} \).

Solution

Para resolver a expressão \( \left(\frac{x}{3}+\frac{y}{5}\right)^{2} \), vamos expandi-la usando a fórmula do quadrado da soma, que é dada por: \[ (a + b)^{2} = a^{2} + 2ab + b^{2} \] Neste caso, temos: - \( a = \frac{x}{3} \) - \( b = \frac{y}{5} \) Agora, vamos calcular cada parte da fórmula: 1. **Calcular \( a^{2} \)**: \[ a^{2} = \left(\frac{x}{3}\right)^{2} = \frac{x^{2}}{9} \] 2. **Calcular \( b^{2} \)**: \[ b^{2} = \left(\frac{y}{5}\right)^{2} = \frac{y^{2}}{25} \] 3. **Calcular \( 2ab \)**: \[ 2ab = 2 \cdot \frac{x}{3} \cdot \frac{y}{5} = \frac{2xy}{15} \] Agora, juntando tudo, temos: \[ \left(\frac{x}{3}+\frac{y}{5}\right)^{2} = \frac{x^{2}}{9} + \frac{2xy}{15} + \frac{y^{2}}{25} \] Portanto, a expressão expandida é: \[ \frac{x^{2}}{9} + \frac{2xy}{15} + \frac{y^{2}}{25} \]

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Extra Insights

Did you know that the expression \( \left(\frac{x}{3}+\frac{y}{5}\right)^{2} \) can be expanded using the binomial theorem? This popular theorem states that \( (a + b)^{n} \) can be expressed as a sum of a certain number of terms, specifically \( \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k} \). In our case, you end up with a neat polynomial involving both \( x \) and \( y \) that makes algebraic manipulations so much easier! Now, if you're applying this in real life, think about it in the context of collaborative projects where teamwork is essential. The parameters \( \frac{x}{3} \) and \( \frac{y}{5} \) can represent contributions from two different team members to a shared goal. Squaring the entire expression could symbolize how collaboration amplifies the effects of each individual's effort. Fun twist, right?

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