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\( \begin{array}{l}\text { Sketch a graph of a tunction that contains } \\ \text { the following: } \\ \text { a) } f(0)=1 \\ \text { b) } \lim _{x \rightarrow 0^{-}} f(x)=-1 \\ \text { c) } \lim _{x \rightarrow 0^{+}} f(x)=2\end{array} \)

Ask by Flynn Elliott. in the United States
Mar 10,2025

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Answer

To sketch the graph of the function \( f(x) \): 1. **Plot the point** at \( (0, 1) \). 2. **Approach** \( y = -1 \) as \( x \) approaches 0 from the left. 3. **Approach** \( y = 2 \) as \( x \) approaches 0 from the right. This creates a graph with a jump discontinuity at \( x = 0 \), where the left-hand limit is -1, the right-hand limit is 2, and the function value at \( x = 0 \) is 1.

Solution

To sketch a graph of a function \( f(x) \) that meets the specified conditions, we need to analyze each condition step by step: 1. **Condition a**: \( f(0) = 1 \) - This means that the function has a point at \( (0, 1) \). 2. **Condition b**: \( \lim_{x \rightarrow 0^{-}} f(x) = -1 \) - This indicates that as \( x \) approaches 0 from the left (negative side), the function approaches -1. Therefore, the graph should approach the line \( y = -1 \) as it gets closer to \( x = 0 \) from the left. 3. **Condition c**: \( \lim_{x \rightarrow 0^{+}} f(x) = 2 \) - This means that as \( x \) approaches 0 from the right (positive side), the function approaches 2. Thus, the graph should approach the line \( y = 2 \) as it gets closer to \( x = 0 \) from the right. ### Sketching the Graph - Start by plotting the point \( (0, 1) \). - Draw a line approaching \( y = -1 \) as \( x \) approaches 0 from the left. This means the graph will be below the point \( (0, 1) \) and will approach \( y = -1 \). - Draw a line approaching \( y = 2 \) as \( x \) approaches 0 from the right. This means the graph will be above the point \( (0, 1) \) and will approach \( y = 2 \). ### Summary of the Graph - The graph will have a discontinuity at \( x = 0 \) since the left-hand limit and right-hand limit do not equal the function value at that point. - The left side of the graph will approach \( y = -1 \) as \( x \) approaches 0 from the left. - The right side of the graph will approach \( y = 2 \) as \( x \) approaches 0 from the right. This creates a jump discontinuity at \( x = 0 \). ### Final Graph The graph can be visualized as follows: - For \( x < 0 \), the graph approaches \( y = -1 \). - At \( x = 0 \), the graph has a point at \( (0, 1) \). - For \( x > 0 \), the graph approaches \( y = 2 \). This sketch represents the function \( f(x) \) that satisfies all the given conditions.

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Beyond the Answer

To create a graph that meets the specified criteria, start by planning three key points around \( x = 0 \). Begin with \( f(0) = 1 \) which means at the point (0, 1), you will have a solid dot. As \( x \) approaches 0 from the left (\( 0^{-} \)), the function should drop down to -1, so you can depict this with a line sloping downwards that ends just before hitting \( (-1) \) on the y-axis as it approaches 0. For \( 0^{+} \), the function should rise sharply up to 2, and again, you can depict this with a rising line that begins just after \( 0 \). The graph should visually show the jump at \( x = 0 \); we'll call this a jump discontinuity where the left-hand limit is -1 and the right-hand limit is 2, with the function actually taking the value 1 at \( x = 0 \). This creates a clear visual representation of these limits and the actual function value at that point. Now, you have a graph with intriguing behavior around \( x = 0 \). It's a beautiful representation of how functions can behave unexpectedly, and it illustrates continuity and discontinuity nicely!

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