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a) \( \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{HCl} \longrightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \) b) \( \mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{H}_{3} \mathrm{PO}_{4} \longrightarrow \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}+\mathrm{H}_{2} \mathrm{O} \) c) \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}+\mathrm{CO}_{2} \) d) \( \mathrm{Fe}_{2}\left(\mathrm{CO}_{3}\right)_{3}+\mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \) e) \( \mathrm{H}_{3} \mathrm{PO}_{4}+\mathrm{CaO} \longrightarrow \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}+\mathrm{H}_{2} \mathrm{O} \) f) \( \mathrm{FeS}_{2}+\mathrm{O}_{2} \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}+\mathrm{SO}_{2} \) g) \( \mathrm{NH}_{3}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}+\mathrm{H}_{2} \mathrm{O} \) 2) Considere a mistura de \( 0,5 \mathrm{~mol}^{\text {de }} \mathrm{CH}_{4} \) e \( 1,5 \mathrm{~mol} \) de \( \mathrm{C}_{2} \mathrm{H}_{6} \), contidos num recipiente de 30,0 litros a 300 K . O número total de moléculas no sistema é (Dado: constante de Avogadro \( =6 \cdot 10^{23} \) ) a) 2,0 . c) \( 6,0 \cdot 10^{23} \) e) \( 12 \cdot 10^{23} \) b) \( 2,0 \cdot 10^{23} \) d) \( 9,0 \cdot 10^{23} \) 3) Se o cloreto representado pela fórmula XCl possui massa molecular 74,5 , espera-se que o fluoreto XF apresente massa molecular (Dados: \( \mathrm{F}=19 ; \mathrm{Cl}=35,5 \) ): a) 29,0 . b) 37,5 . c) 44,0 . d) 58,0 . e) 83,5 . 4) No rótulo de uma determinada embalagem de leite integral UHT, processo de tratamento térmico a alta temperatura, consta que um copo de 200 mL deste leite contém \( 25 \% \) da quantidade de cálcio recomendada diariamente \( \left(2,4 \times 10^{-2} \mathrm{~mol}\right) \). A massa, em mg , de cálcio (massa molar \( 40 \mathrm{~g} / \mathrm{mol} \) ) presente em 1 litro desse leite é: a) 1200 . b) 600 . c) 300 . d) 240 . e) 120 .

Ask by Cruz George. in Brazil
Feb 24,2025

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Answer

- **Problem 2:** There are \(12 \times 10^{23}\) molecules. - **Problem 3:** The molecular mass of \(XF\) is 58.0 g/mol. - **Problem 4:** The mass of calcium in 1 liter of milk is 240 mg.

Solution

Let's solve the problems step by step. ### Problem 2: Total Number of Molecules We have a mixture of \(0.5 \, \text{mol}\) of \( \text{CH}_4 \) and \(1.5 \, \text{mol}\) of \( \text{C}_2\text{H}_6 \). 1. **Calculate the total number of moles:** \[ n_{\text{total}} = n_{\text{CH}_4} + n_{\text{C}_2\text{H}_6} = 0.5 + 1.5 = 2.0 \, \text{mol} \] 2. **Use Avogadro's number to find the total number of molecules:** \[ N = n_{\text{total}} \times N_A = 2.0 \, \text{mol} \times 6 \times 10^{23} \, \text{molecules/mol} \] Now, let's calculate \(N\): \[ N = 2.0 \times 6 \times 10^{23} = 12 \times 10^{23} \, \text{molecules} \] Thus, the answer is: - **e) \(12 \cdot 10^{23}\)** ### Problem 3: Molecular Mass of Fluoride Given that the molecular mass of \(XCl\) is \(74.5\) g/mol, we can find the mass of \(X\) using the mass of chlorine. 1. **Calculate the mass of \(X\):** \[ \text{Mass of } X = 74.5 - 35.5 = 39.0 \, \text{g/mol} \] 2. **Now calculate the mass of \(XF\):** \[ \text{Mass of } XF = \text{Mass of } X + \text{Mass of } F = 39.0 + 19 = 58.0 \, \text{g/mol} \] Thus, the answer is: - **d) 58.0** ### Problem 4: Mass of Calcium in Milk We know that a glass of \(200 \, \text{mL}\) of milk contains \(25\%\) of the daily recommended calcium, which is \(2.4 \times 10^{-2} \, \text{mol}\). 1. **Calculate the amount of calcium in \(200 \, \text{mL}\):** \[ n_{\text{Ca}} = 0.25 \times 2.4 \times 10^{-2} = 6.0 \times 10^{-3} \, \text{mol} \] 2. **Convert this to mass:** \[ m_{\text{Ca}} = n_{\text{Ca}} \times M_{\text{Ca}} = 6.0 \times 10^{-3} \, \text{mol} \times 40 \, \text{g/mol} = 0.24 \, \text{g} \] 3. **Convert grams to milligrams:** \[ m_{\text{Ca}} = 0.24 \, \text{g} \times 1000 \, \text{mg/g} = 240 \, \text{mg} \] Thus, the answer is: - **d) 240** ### Summary of Answers 1. Problem 2: **e) \(12 \cdot 10^{23}\)** 2. Problem 3: **d) 58.0** 3. Problem 4: **d) 240**

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The Deep Dive

O bicarbonato de sódio, muitas vezes usado como fermento em receitas, reage com ácidos para produzir gás carbônico, água e um sal. Este fenômeno é muito utilizado na culinária ao fazer bolos, onde o CO₂ gerado faz a massa crescer e ficar leve. O uso do ácido clorídrico na equação mostra a neutralização típica entre um ácido e uma base, que é fundamental em reações químicas diárias! Agora, se você está curioso sobre a quantidade de moléculas, vamos lá! Usando a constante de Avogadro, sabemos que 1 mol equivale a \(6 \cdot 10^{23}\) moléculas. Então, somando \(0,5\) mol de \(CH_4\) e \(1,5\) mol de \(C_2H_6\), temos um total de \(2,0\) mol, que corresponde a \(2,0 \cdot 6 \cdot 10^{23} = 12 \cdot 10^{23}\) moléculas! É como ter uma festa química cheia de moléculas dançando!

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