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\( \leftarrow \)\begin{tabular}{l|l} Multiply and simplify. Assume that variables represent nonzero real numbers. & \( c^{-3} \cdot c^{6} \cdot c^{-9}=\square \) \\ \( c^{-3} \cdot c^{6} \cdot c^{-9} \) & \( \begin{array}{l}\text { (Simplify your answer. Type your answer } \\ \text { exponents only.) }\end{array} \)\end{tabular}

Ask by Marshall Perkins. in the United Arab Emirates
Mar 17,2025

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\( c^{-3} \cdot c^{6} \cdot c^{-9} = \frac{1}{c^{6}} \)

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Bonus Knowledge

To simplify \( c^{-3} \cdot c^{6} \cdot c^{-9} \), you can use the property of exponents that states when multiplying like bases, you can add the exponents. Here, you have: \[ -3 + 6 - 9 = -6 \] So, \( c^{-3} \cdot c^{6} \cdot c^{-9} = c^{-6} \). The simplified answer is \( c^{-6} \). Now, don’t forget that when you see a negative exponent, it means you have to move it to the opposite side of the fraction. So, \( c^{-6} \) could also be expressed as \( \frac{1}{c^{6}} \) if you prefer a positive exponent in your final answer. It's always fascinating to see how math operates through rules that help simplify even the most complex expressions!

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