Question Find the solution of the system of equations. \[ \begin{array}{r}10 x-2 y=44 \\ -2 x-9 y=10\end{array} \] Answer Attempt 1 out of 2 \( (\square \square, \square) \) Suls answer

**Step 1: Write Down the System** \[ \begin{aligned} 10x - 2y &= 44 \quad \text{(Equation 1)} \\ -2x - 9y &= 10 \quad \text{(Equation 2)} \end{aligned} \] **Step 2: Solve Equation 1 for \( y \)** Starting with Equation 1: \[ 10x - 2y = 44 \] Isolate \( y \): \[ -2y = 44 - 10x \] Divide by \(-2\): \[ y = \frac{10x - 44}{2} = 5x - 22 \] **Step 3: Substitute \( y = 5x - 22 \) in Equation 2** Substitute into Equation 2: \[ -2x - 9(5x - 22) = 10 \] Expand the term: \[ -2x - 45x + 198 = 10 \] Combine like terms: \[ -47x + 198 = 10 \] **Step 4: Solve for \( x \)** Subtract 198 from both sides: \[ -47x = 10 - 198 \] \[ -47x = -188 \] Divide by \(-47\): \[ x = \frac{-188}{-47} = 4 \] **Step 5: Substitute \( x = 4 \) into \( y = 5x - 22 \)** \[ y = 5(4) - 22 = 20 - 22 = -2 \] **Final Answer** \[ (4, -2) \]