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\begin{tabular}{l} Suppose that the dollar value \( v(t) \) of a certain car that is \( t \) years old is given by the following exponential function. \\ \( v(t)=19,900(1.22)^{t} \) \\ \begin{tabular}{|l|}\hline Find the initial value of the car. \\ \hline Does the function represent growth or decay? \\ O growth o decay \\ \hline By what percent does the value of the car change each year? \\ \( \square \% \)\end{tabular} \\ \hline\end{tabular}

Ask by Romero Haynes. in the United States
Mar 15,2025

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Tutor-Verified Answer

Answer

- **Initial Value:** \$19,900 - **Growth or Decay:** Growth - **Annual Percentage Change:** 22%

Solution

**Step 1: Find the initial value of the car.** The initial value is found by evaluating the function at \( t=0 \): \[ v(0)=19,\!900\,(1.22)^0=19,\!900\,(1)=19,\!900. \] Thus, the initial value is \(\$19,\!900\). **Step 2: Determine if the function represents growth or decay.** The function is given by \[ v(t)=19,\!900\,(1.22)^t. \] Since the base \( 1.22 \) is greater than 1, the function represents exponential **growth**. **Step 3: Find the percent change each year.** An exponential function of the form \[ v(t)=\text{initial value}\,(r)^t \] indicates that the value changes by a factor of \( r \) each year. Here, \( r=1.22 \). This means that each year, the value of the car increases by a factor of \( 1.22 \), i.e., there is a \( 1.22 - 1 = 0.22 \) increase relative to the previous year. Converting this to a percentage: \[ 0.22 \times 100\%=22\%. \] Thus, the car’s value increases by **22\%** each year.

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The initial value of the car, when \( t=0 \), can be found by substituting 0 into the function \( v(t) = 19,900(1.22)^{t} \). This gives us \( v(0) = 19,900(1.22)^0 = 19,900(1) = 19,900 \). So, the initial value of the car is $19,900. The function represents growth because the base of the exponent, \( 1.22 \), is greater than 1. Specifically, this means that the value of the car increases as time progresses. To find the percent change each year, we can calculate it as \( (1.22 - 1) \times 100 = 22\% \). Therefore, the value of the car increases by 22% each year!

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