Question Find the solution of the system of equations. \[ 10 x-9 y=-32 \] \[ 2 x-10 y=10 \]
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To solve the system of equations, let's use the substitution or elimination method. Starting with the first equation, rearranging gives: \[ 10x - 9y = -32 \] \[ 10x = 9y - 32 \] \[ x = \frac{9y - 32}{10} \] Now, substitute this expression for \( x \) into the second equation: \[ 2\left(\frac{9y - 32}{10}\right) - 10y = 10 \] \[ \frac{18y - 64}{10} - 10y = 10 \] Multiplying the whole equation by 10 to eliminate the fraction: \[ 18y - 64 - 100y = 100 \] Combining like terms: \[ -82y - 64 = 100 \] Add 64 to both sides: \[ -82y = 164 \] Dividing by -82: \[ y = -2 \] Now substitute \( y = -2 \) back into one of the original equations to find \( x \): Using the first equation: \[ 10x - 9(-2) = -32 \] \[ 10x + 18 = -32 \] \[ 10x = -50 \] \[ x = -5 \] So, the solution to the system of equations is \( x = -5 \) and \( y = -2 \). In ordered pair form, the solution is \( (-5, -2) \).