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Question Find the solution of the system of equations. \[ 10 x-9 y=-32 \] \[ 2 x-10 y=10 \]

Ask by Luna Fuentes. in the United States
Mar 10,2025

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The solution to the system of equations is \( x = -5 \) and \( y = -2 \).

Solución

We start with the system of equations: \[ 10x - 9y = -32 \tag{1} \] \[ 2x - 10y = 10 \tag{2} \] **Step 1.** Multiply equation \((2)\) by \(5\) to match the coefficient of \(x\) in equation \((1)\): \[ 5 \times (2x - 10y) = 5 \times 10 \] which gives: \[ 10x - 50y = 50 \tag{3} \] **Step 2.** Subtract equation \((1)\) from equation \((3)\) to eliminate \(x\): \[ (10x - 50y) - (10x - 9y) = 50 - (-32) \] Simplify the left-hand side: \[ 10x - 50y - 10x + 9y = -41y \] Simplify the right-hand side: \[ 50 + 32 = 82 \] So we have: \[ -41y = 82 \] **Step 3.** Solve for \(y\): \[ y = \frac{82}{-41} = -2 \] **Step 4.** Substitute \(y = -2\) back into equation \((2)\): \[ 2x - 10(-2) = 10 \] Simplify: \[ 2x + 20 = 10 \] Subtract \(20\) from both sides: \[ 2x = -10 \] Divide by \(2\): \[ x = -5 \] Thus, the solution to the system is: \[ (x, y) = (-5, -2) \]

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The Deep Dive

To solve the system of equations, let's use the substitution or elimination method. Starting with the first equation, rearranging gives: \[ 10x - 9y = -32 \] \[ 10x = 9y - 32 \] \[ x = \frac{9y - 32}{10} \] Now, substitute this expression for \( x \) into the second equation: \[ 2\left(\frac{9y - 32}{10}\right) - 10y = 10 \] \[ \frac{18y - 64}{10} - 10y = 10 \] Multiplying the whole equation by 10 to eliminate the fraction: \[ 18y - 64 - 100y = 100 \] Combining like terms: \[ -82y - 64 = 100 \] Add 64 to both sides: \[ -82y = 164 \] Dividing by -82: \[ y = -2 \] Now substitute \( y = -2 \) back into one of the original equations to find \( x \): Using the first equation: \[ 10x - 9(-2) = -32 \] \[ 10x + 18 = -32 \] \[ 10x = -50 \] \[ x = -5 \] So, the solution to the system of equations is \( x = -5 \) and \( y = -2 \). In ordered pair form, the solution is \( (-5, -2) \).

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