2) $$ \begin{array}{r}5 x-4 y=1 \ x-y=-7\end{array} $$

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Solve the system of equations $$ 5x-4y=1;x-y=-7 $$.
Solve the system of equations by following steps:
- step0: Solve using the substitution method:
  $$\left\{ \begin{array}{l}5x-4y=1\x-y=-7\end{array}ight.$$
- step1: Solve the equation:
  $$\left\{ \begin{array}{l}5x-4y=1\x=-7+y\end{array}ight.$$
- step2: Substitute the value of $$x:$$
  $$5\left(-7+yight)-4y=1$$
- step3: Simplify:
  $$-35+y=1$$
- step4: Move the constant to the right side:
  $$y=1+35$$
- step5: Add the numbers:
  $$y=36$$
- step6: Substitute the value of $$y:$$
  $$x=-7+36$$
- step7: Calculate:
  $$x=29$$
- step8: Calculate:
  $$\left\{ \begin{array}{l}x=29\y=36\end{array}ight.$$
- step9: Check the solution:
  $$\left\{ \begin{array}{l}x=29\y=36\end{array}ight.$$
- step10: Rewrite:
  $$\left(x,yight) = \left(29,36ight)$$
The solution to the system of equations is $$ (x,y) = (29,36) $$.
The solution is $$ x=29 $$ and $$ y=36 $$.

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