2) \( \begin{array}{r}5 x-4 y=1 \\ x-y=-7\end{array} \)
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Beyond the Answer
To solve the system of equations, we can use substitution or elimination. First, let's solve the second equation for \(x\): From \(x - y = -7\), we rearrange it to find \(x = y - 7\). Now, we can substitute this expression for \(x\) into the first equation: \[ 5(y - 7) - 4y = 1 \] Expanding this gives: \[ 5y - 35 - 4y = 1 \implies y - 35 = 1 \implies y = 36 \] Now, substitute \(y = 36\) back into \(x = y - 7\): \[ x = 36 - 7 = 29 \] So the solution to the system of equations is \(x = 29\) and \(y = 36\)! In conclusion, the pair \((x, y)\) is \((29, 36)\).
