\( 1<\begin{array}{l}\text { To win at LOTTO in one state, one must correctly select } 6 \text { numbers from a callection of } 68 \\ \text { numbers (1 through 56). The order in which the selection is made does not matter. Howt } \\ \text { many different selections are possible? }\end{array} \) There are \( \square \) different LOTTO selections.

To find the number of different selections possible when choosing 6 numbers from a collection of 68, you can use the combination formula, which is given by: \[ C(n, k) = \frac{n!}{k!(n-k)!} \] In this case, \( n = 68 \) and \( k = 6 \). Plugging in the values, we get: \[ C(68, 6) = \frac{68!}{6!(68-6)!} = \frac{68!}{6! \cdot 62!} = \frac{68 \times 67 \times 66 \times 65 \times 64 \times 63}{6 \times 5 \times 4 \times 3 \times 2 \times 1} = 11238513 \] So, there are **11,238,513** different LOTTO selections possible.