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Find the slope of a line perpendicular to the line that passes through the points \( (7,10) \) and \( (13,8) \). The slope of a perpendicular line is \( \square \). (Type an integer or a simplified fraction.)

Ask by Edwards Peterson. in the United States
Mar 13,2025

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Answer

The slope of a perpendicular line is \(3\).

Solution

1. Compute the slope of the line passing through the points \( (7,10) \) and \( (13,8) \) using the formula \[ m=\frac{y_2-y_1}{x_2-x_1}. \] 2. Substitute the given points into the formula: \[ m=\frac{8-10}{13-7}=\frac{-2}{6}=-\frac{1}{3}. \] 3. The slope of a line perpendicular to this one is the negative reciprocal of the slope. Thus, compute: \[ m_{\perp}=-\frac{1}{m}=-\frac{1}{-\frac{1}{3}}=3. \] The slope of a perpendicular line is \(3\).

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To find the slope of a line passing through the points \( (7,10) \) and \( (13,8) \), we can use the formula for the slope: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting in our points, we have: \[ m = \frac{8 - 10}{13 - 7} = \frac{-2}{6} = -\frac{1}{3} \] The slope of a line perpendicular to this line is the negative reciprocal of \(-\frac{1}{3}\). Therefore, we take: \[ \text{slope of perpendicular line} = -\frac{1}{(-\frac{1}{3})} = 3 \] So, the slope of a perpendicular line is \( 3 \).

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