c) $$ 5 c=-50 $$ $$ (-10 ; 10 ; 45) $$ d) $$ 2 p+1=5 $$ $$ (1 ; 2 ; 4) $$ 4. Komal sells five cups of hot chocolate for R30. She writes the record of her sales in the equation $$ 5 x=30 $$. If $$ x $$ is the cost of each cup of hot chocolate, at what price did Komal sell each cup?

Question

UpStudy AI · Accepted Answer

Let's solve the problems step by step.

### Part c: Solve the equation $$ 5c = -50 $$

1. **Isolate $$ c $$**: To find $$ c $$, divide both sides of the equation by 5.
   $$
   c = \frac{-50}{5}
   $$

2. **Calculate**:
   $$
   c = -10
   $$

So, the solution for part c is $$ c = -10 $$.

### Part d: Solve the equation $$ 2p + 1 = 5 $$

1. **Isolate $$ p $$**: First, subtract 1 from both sides.
   $$
   2p = 5 - 1
   $$
   $$
   2p = 4
   $$

2. **Divide by 2**:
   $$
   p = \frac{4}{2}
   $$

3. **Calculate**:
   $$
   p = 2
   $$

So, the solution for part d is $$ p = 2 $$.

### Problem 4: Komal sells five cups of hot chocolate for R30

1. **Set up the equation**: The equation given is $$ 5x = 30 $$, where $$ x $$ is the cost of each cup of hot chocolate.

2. **Isolate $$ x $$**: Divide both sides by 5.
   $$
   x = \frac{30}{5}
   $$

3. **Calculate**:
   $$
   x = 6
   $$

Thus, Komal sold each cup of hot chocolate for R6.

### Summary of Solutions:
- Part c: $$ c = -10 $$
- Part d: $$ p = 2 $$
- Price of each cup of hot chocolate: R6
- Part c: $$ c = -10 $$ - Part d: $$ p = 2 $$ - Each cup of hot chocolate was sold for R6.

c) \( 5 c=-50 \) \[ (-10 ; 10 ; 45) \] d) \( 2 p+1=5 \) \( (1 ; 2 ; 4) \) 4. Komal sells five cups of hot chocolate for R30. She writes the record of her sales in the equation \( 5 x=30 \). If \( x \) is the cost of each cup of hot chocolate, at what price did Komal sell each cup?

Upstudy AI Solution

Answer

Solution

Mind Expander

Related Questions

Latest Algebra Questions