c) \( 5 c=-50 \) \[ (-10 ; 10 ; 45) \] d) \( 2 p+1=5 \) \( (1 ; 2 ; 4) \) 4. Komal sells five cups of hot chocolate for R30. She writes the record of her sales in the equation \( 5 x=30 \). If \( x \) is the cost of each cup of hot chocolate, at what price did Komal sell each cup?

Let's solve the problems step by step. ### Part c: Solve the equation \( 5c = -50 \) 1. **Isolate \( c \)**: To find \( c \), divide both sides of the equation by 5. \[ c = \frac{-50}{5} \] 2. **Calculate**: \[ c = -10 \] So, the solution for part c is \( c = -10 \). ### Part d: Solve the equation \( 2p + 1 = 5 \) 1. **Isolate \( p \)**: First, subtract 1 from both sides. \[ 2p = 5 - 1 \] \[ 2p = 4 \] 2. **Divide by 2**: \[ p = \frac{4}{2} \] 3. **Calculate**: \[ p = 2 \] So, the solution for part d is \( p = 2 \). ### Problem 4: Komal sells five cups of hot chocolate for R30 1. **Set up the equation**: The equation given is \( 5x = 30 \), where \( x \) is the cost of each cup of hot chocolate. 2. **Isolate \( x \)**: Divide both sides by 5. \[ x = \frac{30}{5} \] 3. **Calculate**: \[ x = 6 \] Thus, Komal sold each cup of hot chocolate for R6. ### Summary of Solutions: - Part c: \( c = -10 \) - Part d: \( p = 2 \) - Price of each cup of hot chocolate: R6