3. Which one is the slope of the line passing through the points \( A(3,-2) \) and \( B(2,2) \) ? A) -4 B) -2 C) 1 D) 2 E) 3 8. Let \( A(2,1), B(-2,3) \) and \( C(4,1) \) be three points. Which one(s) of the following(s) is/are false? 1. \( A B \) is parallel to the \( x \)-axis. II. \( A C \) is parallel to the \( x \)-axis. III. The slope of line \( A C \) is 0 . IV. The slope of line BC is \( -\frac{1}{3} \) A) I only B) II only D) \( I \) and III E) III and IV
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Bonus Knowledge
To find the slope of the line passing through the points \( A(3,-2) \) and \( B(2,2) \), we use the formula for slope: \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Plugging in the coordinates: \( m = \frac{2 - (-2)}{2 - 3} = \frac{4}{-1} = -4 \). So, the answer is A) -4! For the second question, let's analyze the statements about the points \( A(2,1) \), \( B(-2,3) \), and \( C(4,1) \). The line \( A B \) is not parallel to the \( x \)-axis because it has differing \( y \)-coordinates (1 and 3), making statement I false. Meanwhile, both points \( A(2,1) \) and \( C(4,1) \) have the same \( y \)-coordinate; thus \( A C \) is indeed parallel to the \( x \)-axis, making II true. A slope of 0 also confirms III as true. Lastly, calculating the slope for line \( BC \) gives us \( m = \frac{1 - 3}{4 - (-2)} = \frac{-2}{6} = -\frac{1}{3} \), affirming IV as true. Therefore, the false statement is I only (A).