1.2. Between which two consecutive integers does $$ \sqrt{138} $$ - lie? (3) 1.3. Rewrite 0,26 as a proper fraction (in the form of $$ \frac{a}{b} $$ ), show all steps. (4)

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### 1.2. Finding the consecutive integers between which $$ \sqrt{138} $$ lies

1. Recognize that for an integer $$ n $$, the square $$ n^2 $$ must be compared to 138.
2. Calculate $$ 11^2 $$ and $$ 12^2 $$:
   - $$ 11^2 = 121 $$
   - $$ 12^2 = 144 $$
3. Since $$ 121 < 138 < 144 $$, it follows that 
   $$
   11 < \sqrt{138} < 12.
   $$

### 1.3. Rewriting 0,26 as a proper fraction

1. Express the decimal $$ 0,26 $$ (or $$ 0.26 $$) as a fraction with denominator 100:
   $$
   0.26 = \frac{26}{100}.
   $$
2. Simplify the fraction by dividing the numerator and the denominator by their greatest common divisor, which is $$ 2 $$:
   $$
   \frac{26 \div 2}{100 \div 2} = \frac{13}{50}.
   $$
3. Thus, the proper fraction form is:
   $$
   \frac{13}{50}.
   $$
1.2. $$ \sqrt{138} $$ lies between 11 and 12. 1.3. $$ 0.26 = \frac{13}{50} $$.

1.2. Between which two consecutive integers does \( \sqrt{138} \) - lie? (3) 1.3. Rewrite 0,26 as a proper fraction (in the form of \( \frac{a}{b} \) ), show all steps. (4)

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