1.2. Between which two consecutive integers does \( \sqrt{138} \) - lie? (3) 1.3. Rewrite 0,26 as a proper fraction (in the form of \( \frac{a}{b} \) ), show all steps. (4)

To find between which two consecutive integers \( \sqrt{138} \) lies, we first notice that \( 12^2 = 144 \) and \( 11^2 = 121 \). Since \( 121 < 138 < 144 \), we can deduce that \( 11 < \sqrt{138} < 12 \). Therefore, \( \sqrt{138} \) lies between the consecutive integers 11 and 12. To rewrite 0.26 as a proper fraction, we start by recognizing that 0.26 can be expressed as \( \frac{26}{100} \). To simplify, we need to find the greatest common divisor (GCD) of 26 and 100, which is 2. Now we divide both the numerator and the denominator by 2: \( \frac{26 ÷ 2}{100 ÷ 2} = \frac{13}{50} \). Thus, 0.26 as a fraction is \( \frac{13}{50} \).