Ifm $$ \angle D A B=75^{\circ} $$, ma $$ \angle A D C $$ 25 100 105 115

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We are given that
$$
\angle DAB=75^\circ.
$$
A common configuration in geometry problems is when four points $$ A $$, $$ B $$, $$ C $$, and $$ D $$ lie on a circle (i.e. they form a cyclic quadrilateral). In a cyclic quadrilateral the sum of the measures of two opposite angles is $$ 180^\circ $$. If we assume that the given angle $$ \angle DAB $$ and the angle $$ \angle ADC $$ are opposite angles, then we have

$$
\angle DAB + \angle ADC = 180^\circ.
$$

Substituting the given value, we get

$$
75^\circ + \angle ADC = 180^\circ.
$$

Now, solving for $$ \angle ADC $$:

$$
\angle ADC = 180^\circ - 75^\circ = 105^\circ.
$$

Thus, the measure of $$ \angle ADC $$ is

$$
\boxed{105^\circ}.
$$
The measure of $$ \angle ADC $$ is $$ 105^\circ $$.

Ifm \( \angle D A B=75^{\circ} \), ma \( \angle A D C \) 25 100 105 115

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