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9. \( 3-5 \cdot \log _{3} x=2 \)

Ask by Chambers Norris. in the United States
Mar 18,2025

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Tutor-Verified Answer

Answer

\( x = \sqrt[5]{3} \)

Solution

Solve the equation \( 3-5 \cdot \log _{3} x=2 \). Solve the equation by following steps: - step0: Solve for \(x\): \(3-5\log_{3}{\left(x\right)}=2\) - step1: Find the domain: \(3-5\log_{3}{\left(x\right)}=2,x>0\) - step2: Move the expression to the left side: \(3-5\log_{3}{\left(x\right)}-2=0\) - step3: Subtract the numbers: \(1-5\log_{3}{\left(x\right)}=0\) - step4: Rewrite the expression: \(-5\log_{3}{\left(x\right)}=-1\) - step5: Change the sign: \(5\log_{3}{\left(x\right)}=1\) - step6: Divide both sides: \(\frac{5\log_{3}{\left(x\right)}}{5}=\frac{1}{5}\) - step7: Divide the numbers: \(\log_{3}{\left(x\right)}=\frac{1}{5}\) - step8: Convert the logarithm into exponential form: \(x=3^{\frac{1}{5}}\) - step9: Transform the expression: \(x=\sqrt[5]{3}\) - step10: Check if the solution is in the defined range: \(x=\sqrt[5]{3},x>0\) - step11: Find the intersection: \(x=\sqrt[5]{3}\) The solution to the equation \(3-5 \cdot \log _{3} x=2\) is \(x=\sqrt[5]{3}\).

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Bonus Knowledge

To solve the equation \( 3-5 \cdot \log _{3} x=2 \), start by isolating the logarithmic term. Subtract 3 from both sides to get \( -5 \cdot \log_{3} x = -1 \). Dividing both sides by -5 gives \( \log_{3} x = \frac{1}{5} \). Now, we can rewrite this in exponential form: \( x = 3^{\frac{1}{5}} \). Thus, the solution is \( x = \sqrt[5]{3} \). Now, how about trying to visualize logarithms? Imagine a world where every number is a cozy little house, and logarithms are the nifty GPS guides helping you find the location of your number in a vast neighborhood called the "number line." They might seem daunting initially, but they transform exponential growth into a more manageable form, making them essential in fields ranging from science to finance! For further exploration, investigating the properties of logarithms can be a treasure trove of insight! Check out how they relate to exponential functions, the change of base formula, or even graphing logarithmic functions. Books like "Understanding Analysis" by Stephen Abbott or "The Joy of x" by Steven Strogatz can offer an engaging approach to these topics, laying a solid foundation in both theory and real-life applications. Happy learning!

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