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Find the product. \[ (2 x+2)^{2} \]

Ask by Hobbs Carroll. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

The product is \(4x^2 + 8x + 4\).

Solution

1. Recognize that the square of a binomial is given by \[ (a+b)^2 = a^2 + 2ab + b^2. \] 2. In the expression \((2x+2)^2\), let \[ a = 2x \quad \text{and} \quad b = 2. \] 3. Compute each term: - \(a^2 = (2x)^2 = 4x^2\), - \(2ab = 2\cdot (2x)\cdot 2 = 8x\), - \(b^2 = 2^2 = 4\). 4. Combine the results: \[ (2x+2)^2 = 4x^2 + 8x + 4. \]

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The Deep Dive

To find the product of \( (2x + 2)^2 \), we will use the formula for the square of a binomial, which states that \( (a + b)^2 = a^2 + 2ab + b^2 \). Here, let \( a = 2x \) and \( b = 2 \). Now, applying the formula: 1. Square \( a \): \( (2x)^2 = 4x^2 \) 2. Square \( b \): \( 2^2 = 4 \) 3. Calculate \( 2ab \): \( 2 \cdot (2x) \cdot 2 = 8x \) Putting it all together: \[ (2x+2)^2 = 4x^2 + 8x + 4 \] So, the final result is: \[ \boxed{4x^2 + 8x + 4} \]

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