There are two squares. The perimeter of Square X is half the perimeter of Square Y . How do the areas of the two squares compare? A. The area of Square X is one-sixteenth the area of Square Y . B. The area of Square X is one-eighth the area of Square Y . C. The area of Square X is one-fourth the area of Square Y . D. The area of Square X is one-half the area of Square Y .

Let's break this down in a fun way! If the perimeter of Square X is half that of Square Y, then we can express this using the formula for perimeter (P = 4s, where s is the side length of the square). So, if Square Y has a side length of "s", its perimeter is 4s. Therefore, Square X, having a perimeter that is half, must have a side length of "s/2". Now, calculating the areas! The area of Square X would be (s/2)² = s²/4, and the area of Square Y would be s². When we compare the two areas, we find that Square X's area is indeed one-fourth that of Square Y’s area. So, the answer is C. You see, math can be a piece of cake—sweet and satisfying once you get the layers right! 🍰 Plus, discovering these relationships is a lot like piecing together a puzzle; everything starts to fit together when you look closely!