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3. A chemistry experiment calls for no more thar 0.225 ounce of aeid. Which number below is less thar \( 0.225 ? \)

Ask by Newton Kirk. in the United States
Mar 18,2025

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\(0.222\) is less than \(0.225\).

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The Deep Dive

To find a number that's less than 0.225 ounces, consider common fractions or decimals like 0.2, 0.1, or even 0.225 itself, but remember to keep it strictly under that limit! For example, 0.2 ounces fits the bill perfectly since it's just below 0.225. Now, if you were to visualize this with some fun comparisons, think of 0.225 ounces like a small drizzle of oil in your kitchen - wonderful for cooking but just a tad too much if you’re looking to keep things light. So aim for that perfect undercut with numbers like 0.2 that won’t spill over into excess!

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Complete each of the following nuclear decay equations by determining the mass number and atomic number of the following isotopes after they have emitted either a beta particle, an alpha particle or gamma radiation. Use the periodic table to assist you in identifying the remaining particle. a. \( \begin{array}{r}210 \\ 82 \\ \mathrm{~Pb}\end{array} \rightarrow \quad{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) 1. \( \begin{array}{lll}\frac{1}{\vdots} & \mathrm{~T} \\ \vdots & \rightarrow & 0 \gamma+ \\ \vdots & & 0\end{array} \) \( \qquad \) b. \( { }_{84}^{209} \mathrm{PO} \rightarrow{ }_{82}^{205} \mathrm{~Pb}+ \) \( \qquad \) j. \( { }_{90}^{234} \mathrm{Th} \rightarrow{ }_{91}^{234} \mathrm{~Pa}+ \) \( \qquad \) c. \( { }_{92}^{239} \mathrm{U} \rightarrow \quad{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) d. \( { }_{92}^{238} \mathrm{U} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) k. \( { }_{94}^{239} \mathrm{Pu} \rightarrow \quad{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) I. \( { }_{13}^{27} \mathrm{Al} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) e. \( \begin{array}{r}228 \\ 93 \\ \mathrm{~Np}\end{array} \rightarrow \quad-1 \mathrm{e}+ \) \( \qquad \) f. \( \begin{array}{l}42 \\ 19\end{array} \mathrm{~K} \quad{ }_{19}^{42} \mathrm{~K}+ \) \( \qquad \) m. \( { }_{13}^{27} \mathrm{Al} \rightarrow{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) g. \( { }_{88}^{226} \mathrm{Ra} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) ก. \( { }_{4}^{9} \mathrm{Be} \rightarrow{ }_{4}^{9} \mathrm{Be}+ \) \( \qquad \)

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Complete each of the following nuclear decay equations by determining the mass number and atomic number of the following isotopes after they have emitted either a beta particle, an alpha particle or gamma radiation. Use the periodic table to assist you in identifying the remaining particle. a. \( \begin{array}{r}210 \\ 82 \\ \mathrm{~Pb}\end{array} \rightarrow \quad{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) 1. \( \begin{array}{lll}\frac{1}{\vdots} & \mathrm{~T} \\ \vdots & \rightarrow & 0 \gamma+ \\ \vdots & & 0\end{array} \) \( \qquad \) b. \( { }_{84}^{209} \mathrm{PO} \rightarrow{ }_{82}^{205} \mathrm{~Pb}+ \) \( \qquad \) j. \( { }_{90}^{234} \mathrm{Th} \rightarrow{ }_{91}^{234} \mathrm{~Pa}+ \) \( \qquad \) c. \( { }_{92}^{239} \mathrm{U} \rightarrow \quad{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) d. \( { }_{92}^{238} \mathrm{U} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) k. \( { }_{94}^{239} \mathrm{Pu} \rightarrow \quad{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) I. \( { }_{13}^{27} \mathrm{Al} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) e. \( \begin{array}{r}228 \\ 93 \\ \mathrm{~Np}\end{array} \rightarrow \quad-1 \mathrm{e}+ \) \( \qquad \) f. \( \begin{array}{l}42 \\ 19\end{array} \mathrm{~K} \quad{ }_{19}^{42} \mathrm{~K}+ \) \( \qquad \) m. \( { }_{13}^{27} \mathrm{Al} \rightarrow{ }_{-1}^{0} \mathrm{e}+ \) \( \qquad \) g. \( { }_{88}^{226} \mathrm{Ra} \rightarrow{ }_{2}^{4} \mathrm{He}+ \) \( \qquad \) ก. \( { }_{4}^{9} \mathrm{Be} \rightarrow{ }_{4}^{9} \mathrm{Be}+ \) \( \qquad \)
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