Question
A worker pushes a wheelbarrow with a force of 40 N over a level distance of 6.0 m . If a frictional force of 24 N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow? 1) 240 J 2) 216 J 3) 144 J 4) 96 J 5) 75 J
Ask by Wagner Delgado. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The net work done on the wheelbarrow is 96 J.
Solution
To find the net work done on the wheelbarrow, first determine the work done by each force and then sum them.
1. The worker does work with a force of 40 N over 6.0 m:
Work by the worker = 40 N × 6.0 m = 240 J.
2. Friction, acting opposite to the motion, does negative work:
Work by friction = - (24 N × 6.0 m) = -144 J.
3. The net work is the sum of these contributions:
Net Work = 240 J + (–144 J) = 96 J.
Thus, the net work done on the wheelbarrow is 96 J (choice 4).
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Simplify this solution Beyond the Answer
To find the net work done on the wheelbarrow, we need to calculate the net force acting on it. The worker applies a force of 40 N, while there is a frictional force of 24 N opposing this motion, resulting in a net force of: Net Force = 40 N - 24 N = 16 N. Now, we can find the work done using the formula: Work = Net Force × Distance. Substituting the values we have: Work = 16 N × 6.0 m = 96 J. So, the net work done on the wheelbarrow is 96 J, which corresponds to option 4.
