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3.) \( 7 y=\frac{(x+4)}{2}, \quad \) 4. \( \frac{y-3}{4}-3=\frac{x-\sqrt[3]{8}}{2} \)

Ask by Schmidt Ryan. in Colombia
Mar 14,2025

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Las soluciones son \( x = -\frac{50}{9} \) y \( y = -\frac{1}{9} \).

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To solve the first equation, let's isolate \(y\). Multiply both sides by \(2\): \( 14y = x + 4 \). Then, rearranging gives us \( y = \frac{x + 4}{14} \). For the second equation, simplify as follows: First, add \(3\) to both sides to get \(\frac{y - 3}{4} = \frac{x - 2}{2}\). Now, cross-multiply to find: \( (y - 3) \cdot 2 = (x - 2) \cdot 4 \). This expands to \(2y - 6 = 4x - 8\), or rearranging gives us \(2y - 4x = -2\). These transformations let you visualize the relationships between \(x\) and \(y\) in terms of lines in a coordinate system!

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